Chapter Fourteen — Quadratic Equations and Inequalities
The Humongous Book of Algebra Problems
300
Rationalize by multiplying the numerator and denominator by .
The solution to the equation is , , or .
Completing the Square
Make a trinomial into a perfect square
14.12 Given the quadratic expression x
2
– 8x + n, identify the value of n that makes
the trinomial a perfect square and verify your answer.
Divide the coefficient of x by 2.
–8 ÷ 2 = –4
Square the quotient.
(–4)
2
= 16
Substituting n = 16 into the expression creates the perfect square x
2
– 8x + 16. To
verify that the quadratic is a perfect square, factor it.
x
2
– 8x + 16 = (x – 4)(x – 4) = (x – 4)
2
14.13 Given the expression x
2
– 3x + b, identify the value of b that makes the
trinomial a perfect square.
Apply the technique outlined in Problem 14.12: divide the coefficient of x by 2
(that is, multiply it by ) and square the result.
14.14 Solve the equation by completing the square: x
2
– 6x = 0.
Convert the quadratic binomial x
2
– 6x into a perfect square quadratic trinomial
by dividing the coefficient of x by 2 (–6 ÷ 2 = –3) and squaring the result
([–3]
2
= 9).
x
2
– 6x + 9 = 0 + 9
Notice that you cannot add 9 only to the left side of the equation. Any real
number added to one side of the equation must be added to the other side
as well.
x
2
– 6x + 9 = 9
The equation
is allowed to
have up to three
real number solutions
because the highest
power of x in the
original equation
was 3.
x
2
– 8x + 16
is a perfect
square because it’s
equal to some quantity
multiplied times itself:
(x – 4)(x – 4). It’s the
same logic that makes
25 a perfect square:
5
˙
5 = 25.
This trick only
works if you have
an x
2
-term with a
coefcient of 1
and an x-term.