Chapter Four — Linear Equations in One Variable
The Humongous Book of Algebra Problems
70
Absolute Value Equations
Most of them have two solutions
4.29 What values of x satisfy the equation ?
This absolute value equation has two valid solutions, the value on the left side of
the equation and its opposite: x = 6 or x = –6. Substituting either for x results in
a true statement.
The solutions to the equation (where r is a positive real number) are
r and –r.
4.30 Solve the equation for x and verify the solutions.
Isolate the absolute value expression left of the equal sign by adding 3 to both
sides of the equation.
According to Problem 4.29, x = –4 or x = 4.
To verify the solutions, substitute each into the original equation and verify that
the results are true statements.
4.31 Explain why the equation has no real solutions.
The expression left of the equal sign, , is entirely enclosed by absolute
value bars. Therefore, the left side of the equation must be positive no matter
what value of x is substituted into it. The right side of the equation contains a
negative constant, –8. If the left side of the equation must be positive for all
real x and the right side of the equation is always negative, no x–value can be
substituted into the equation that results in a true statement.
Use the
word “or”
to separate
possible solutions,
because you get a
true statement by
plugging either x = 6
OR x = –6 into the
equation.
So whatever’s
inside the
absolute value
bars either equals
the left side of
the equation or the
opposite of the
left side.
After you
isolate the
absolute value
on the left side of
the equation, set
whatever’s inside the
bars (in this case x)
equal to the right side
of the equation (4)
and the opposite of
that number (–4).
Those are the
solutions.