Chapter Four — Linear Equations in One Variable
The Humongous Book of Algebra Problems
59
Subtract 10 from both sides of the equation to isolate x.
The solution to the equation is x = 26. Verify the solution by substituting it into
the original equation.
Because substituting x = 26 into the equation produces a true statement
(114 = 114), x = 26 is the correct solution.
Multiplying and Dividing to Solve an Equation
Multiply/divide both sides
Note: Problems 4.9–4.10 refer to the statement “the product of three and a number is 42.”
4.9 Express the statement as an algebraic equation in terms of x.
The word “product” indicates multiplication—the product of 3 and a number x
is 3 · x, or 3x. According to the problem, that product is equal to 42: 3x = 42.
Note: Problems 4.9–4.10 refer to the statement “the product of three and a number is 42.”
4.10 Solve the equation generated in Problem 4.9 for x.
To solve an equation, you must isolate x on one side of the equal sign. In this
case, isolating x requires you to eliminate the coefficient 3; to do so, divide both
sides of the equation by 3.
Reduce the fraction to lowest terms.
3 and x
are multiplied,
so to get rid
of 3, you have
to do the
opposite of
multiplying:
dividing.