3.2. DIMENSION DESIGN WITH REQUIRED RELIABILITY 137
Per Section 3.2.1, we can determine the dimension-dependent parameters K
t
for static design
or K
f
and k
b
for fatigue design if necessary.
Step 2: Establish the limit state function.
For a clear description of the modified R-F method procedure, we can rearrange the limit
state function (3.1) into the following form of the limit state function.
g
.
X
1
; : : : ; X
r
; X
rC1
; : : : ; X
n
; d
/
D
8
ˆ
ˆ
<
ˆ
ˆ
:
> 0 Safe
D 0 Limit state
< 0 Failure;
(3.18)
where the first r random variables are non-normal distributed random variables and the rest
.n r/ random variables are normally distributed random variables. e last one is normally
distributed dimension with a mean
d
and a standard deviation
d
.
Step 3: Calculate the reliability index ˇ.
According to the required reliability of the component, we can determine the reliability index ˇ
per Equation (3.2) and is redisplayed here:
ˇ D ˆ
1
.
R
/
D norminv
.
R
/
: (3.2)
Step 4: Calculate the mean for non-normal distributed random variables.
For non-normally distributed random variables, we can calculate their means based on their type
of distributions, which was discussed in Chapter 3 of Volume 1 [1].
Step 5: Pick an initial design point P
0
X
0
1
; : : : ; X
0
r
; X
0
rC1
; : : : ; X
0
n
; d
0
.
e initial design point could be any point, but it must be on the surface of the limit state
function. Typically, we can use the means of the first n random variables as the values X
0
i
.i D
1; : : : ; n/ in the initial design point, the value d
0
will be determined by the limit state function:
X
0
i
D
X
i
i D 1; 2; : : : ; n
g
X
0
1
; : : : ; X
0
n
; d
0
D 0;
(3.19)
where
X
i
is the mean of every random variable X
i
.i D 1; : : : ; n/. For a non-normally dis-
tributed random variable X
i
.i D 1; : : : ; r/, we will use the mean values that have been calculated
in Step 4.
When the actual limit state function is provided, we can rearrange the second equation
in Equation (3.19) and express d
0
by using X
0
1
; X
0
2
; : : : , and X
0
n
. Let’s use the following
equation to represent this:
d
0
D g
1
X
0
1
; X
0
2
; : : : ; X
0
n
: (3.20)