In this chapter, we consider a setting similar to the economic order quantity (EOQ) model (Section 3.2) but with stochastic demand. The mean demand per year is . The inventory position is monitored continuously, and orders may be placed at any time. There is a deterministic lead time L ( ). Unmet demands are backordered.
If the demand has a continuous distribution, then the inventory level decreases smoothly but randomly over time, with rate , as in Figure 5.1. (Think of liquid draining out of a tank at a fluctuating rate.) This is the interpretation used in most of this chapter. Or demands may occur at discrete points in time (as customers arrive), for example, if the demand follows a Poisson process, as in Section 5.5.
We'll assume the firm follows an policy: When the inventory position reaches a certain point (call it r), we place an order of size Q. L years later, the order arrives. In the intervening time, the inventory on hand may have been sufficient to meet demand, or we may have stocked out. Note that the inventory level (solid line in Figure 5.1) and inventory position (dashed line) differ from each other during lead times but coincide otherwise. An policy is known to be optimal for the setting described here, although we will not prove this.
Whereas the EOQ model has a single decision variable Q, an policy has two decision variables: Q (the order quantity , sometimes called the batch size ) and r (the reorder point) . Our goal is to determine the optimal r and Q to minimize the expected cost per year.
In a continuous‐review setting, policies are equivalent to policies (Section 4.4) as long as the inventory position equals s exactly at some point in every inventory cycle. This is guaranteed for continuous demand distributions (as in Sections 5.2–5.4) and for discrete demands in which each customer demands a single unit (as in Section 5.5). Recall that in an policy, when the inventory position reaches s, we order up to S. Therefore, a given policy is equivalent to an policy in which and . On the other hand, this equivalence does not hold for “lumpy” demand processes such as compound Poisson or for periodic‐review systems, since in either case the inventory position may fall strictly below the reorder point before a replenishment order is placed.
In this chapter, we will focus first on the case in which the demands have a continuous distribution . We will discuss an exact model for this problem in Section 5.2, then discuss several common approximations in Section 5.3, and finally return to the exact model in Section 5.4 to prove some important properties of the optimal solution and its relationship to the economic order quantity with backorders (EOQB). Then, in Section 5.5, we discuss an exact model with discrete demands.
In this section, we introduce an exact model for systems with continuous demand distributions. We first formulate the expected cost function and then derive optimality conditions for it.
We continue to consider the usual costs: fixed cost , purchase cost , holding cost , and stockout cost . We'll use D to represent the lead‐time demand ; D is a random variable with mean , variance , pdf , and cdf . It is important to remember that D, , , etc. refer to lead‐time demand, not to demand per year. Of course, the two are closely related. If the demand per year has mean and standard deviation and the lead time is L years, then the lead‐time demand has mean and standard deviation , assuming independence of demand across time.
Our first step is to derive an exact expression for the expected cost as a function of r and Q. We place orders, on average, every years (just as in the EOQ problem ). Therefore, the expected fixed cost is given by . As in the EOQ, the annual purchase cost is given by . Since it's independent of both Q and r, we'll ignore it in the cost calculations. It remains to evaluate the expected holding and stockout costs, which we will refer to collectively as the inventory cost. The inventory cost is incurred based on the inventory level, , a random variable whose distribution is difficult to determine for the same reasons as for periodic‐review models with nonzero lead times; namely, that it depends on r and Q and that inventory decisions made at time t do not have an effect on until time .
The solution to this problem is to use the conservation‐of‐flow concept discussed in Section 4.3.4.1, in which we relate the inventory level at time to the inventory position at time t (whose probability distribution, as we will see, is easy) and to the demand in the time interval (whose probability distribution we know). In particular, if the inventory position at time t is given by , then the inventory level at time is given by
where is the cumulative demand that occurs between t and . The reasoning is identical to that in Section 4.3.4.1, adjusted for continuous review: All of the items included in —including items on hand and on order—will have arrived by time , and no items ordered after time t will have arrived by time . Therefore, all items that are on hand or on order at time t will be included in the inventory level at time , except for the items that have since been demanded.
As in the periodic‐review case, we can drop the time indices from 5.1 in steady state and write
where D is the lead‐time demand. Zipkin (1986b) shows that 5.2 also holds—and therefore, so do many of the results in the rest of this section—under a range of stochastic lead‐time settings.
Once we determine the distribution of , the (unconditional) expected inventory cost then follows from the law of total expectation. In particular, let be the rate at which the inventory cost accrues when :
( is a rate because the inventory level is changing continuously over time, given in units of money per year.) Then the expected inventory cost per year is
where
is the rate at which the expected inventory cost accrues at time when the inventory position at time t equals y. The expectation in 5.5 is over the lead‐time demand. Note that , with two arguments, is the expected total expected cost, whereas , with one argument, is the expected inventory cost.
is simply the newsvendor expected cost function (Section 4.3.2). Let be its optimizer, given by (4.17).
It remains to determine the distribution of . By the definition of an policy, we know that takes values only in . It turns out that has a very simple distribution—it is uniform on , under some mild conditions on the lead‐time demand distribution (Serfozo and Stidham, 1978; Browne and Zipkin, 1991). Therefore, 5.4 implies that
Combining the expected inventory cost 5.6 and the expected fixed cost , we get the following expression for the expected total cost per year:
For early derivations of this equation, see, e.g., Hadley and Whitin (1963).
Zheng (1992) proves the following:
In what follows, we use the expected cost expression 5.7 to derive optimality conditions for r and Q by first fixing Q and finding the optimal corresponding r, and then optimizing over Q. Although these conditions tell us when a given solution is optimal, they do not give us an algorithm for finding such solutions. Before developing such an algorithm, we first discuss several common approximations for finding the optimal parameters for an policy, in Section 5.3. We then return to the exact model in Section 5.4, proving properties of these optimal solutions that we can use to develop an algorithm.
We will optimize sequentially: . Let be the optimal r for a given Q.
The inventory position equals at the start of a replenishment cycle (just after an order is placed) and equals r at the end (just before the next order is placed). Therefore, Lemma 5.2 says that, for a given Q, the optimal r makes the inventory cost rates equal at the start and end of the replenishment cycle. (See Figure 5.2.) In between, the inventory costs are lower, due to the convexity of .
The motivation behind this result is that, during one replenishment cycle, we need to pass through all of the inventory positions in , and we spend an equal amount of time in each. For fixed Q, we minimize the total cost by choosing the r that keeps as small as possible over those inventory positions. Since is convex, the r that keeps as small as possible over is the r for which .
This result can be visualized as follows. Imagine a two‐dimensional bowl shaped like the function . For a given Q, we can find the optimal value of r by dropping a horizontal bar of length Q into the bowl; then equals the height of the bar when it comes to rest.
We can now characterize the optimal pair.
Theorem 5.1 says that, surprisingly, not only are the inventory costs equal at the start and end of the replenishment cycle, but these costs are also equal to the total cost per year. For some very simple demand distributions, the simultaneous equations 5.10 can be solved analytically. More commonly, though, 5.10 must be solved using an iterative algorithm. In order to derive such an algorithm, we will need some additional properties of the model. Before delving into those, however, we will shift our attention to approximate models.
The first approximation we discuss is probably the best known and most widely covered approximation to find r and Q. (Unfortunately, it is also one of the least accurate; see Section 5.3.5.) It dates back to Whitin (1953) (whose book in fact contains one of the earliest attempts to optimize r and Q simultaneously) as well as to subsequent developments by Hadley and Whitin (1963). We call this the expected‐inventory‐level (EIL) approximation, for reasons that will become clear shortly.
The approach relies on the following two simplifying assumptions to make the model tractable:
Neither assumption is particularly realistic, but we make them for mathematical convenience. SA1 is obviously untrue, since it suggests we earn a holding “credit” when , but it is not too inaccurate if the expected number of stockouts is small. SA2 is not as outrageous, but it is not typical, either in practice or in other inventory models. (Actually, SA1 would not be problematic at all if we didn't also assume SA2. If the stockout cost were charged per year, then we could simply replace the stockout cost p with , thus canceling the artificial “credit” of h for negative inventory .)
In this section, we will derive an expression for the approximate expected cost per year as a function of the decision variables Q and r.
Holding Cost: Figure 5.3 contains a graph of the expected inventory over time. s is the expected on‐hand inventory when the order arrives:
In other words, s is the safety stock —the extra inventory held on hand to meet demand in excess of the mean.
The average inventory level is
By SA1, the expected holding cost per year is
Of course, this expression is only approximate. The essence of the approximation is that we are calculating the expected holding cost as (provided that ), whereas it actually equals , and the two are not equal. That is why we refer to this as the “expected‐inventory‐level” approximation. The problem is more difficult without SA1 because of the nonlinearity introduced by the operator. As previously noted, the EIL approximation becomes less accurate as the expected number of stockouts increases or, equivalently, as s decreases.
Fixed Cost: The expected fixed cost per year is given by K times the expected number of orders per year. From Figure 5.3, we see that . Therefore, the expected cost per year is
Stockout Cost: The expected number of stockouts per order cycle is given by
where is the loss function for the lead‐time demand distribution. (See Section 4.3.2.2 or Section C.3.1.) The expected number of stockouts per year is . By SA2, the expected stockout cost per year is simply
Note that we are assuming that , which is a reasonable assumption in practice. (The reason we make simplifying assumption SA2 is that if the stockout cost were charged per year, then the integrand in the expected stockout cost per year would contain in place of , and this would be significantly harder to analyze. See Problem 5.23.)
Total Cost: Combining 5.12, 5.13, and 5.15, we get the total expected cost per year:
As in the EOQ model, we will optimize by setting the first derivative to 0. Since there are two decision variables, we must take partial derivatives with respect to each and set them both to 0:
or
And:
(using (C.15)), so
Now we have two equations with two unknowns, but these equations cannot be solved in closed form. The approach given in Algorithm 5.1 first sets Q equal to the EOQ quantity, i.e., ignoring the demand randomness. It then proceeds iteratively, solving 5.18 to find r, solving 5.17 to find Q, and so on. The algorithm terminates when one (or both) of the parameters haven't changed much since the last iteration. ( is the convergence tolerance.) Hadley and Whitin (1963) prove that this algorithm converges to the optimal r and Q for 5.16—though it's important to keep in mind that 5.16 itself is only an approximate cost function.
Typically, and , so that the argument to in 5.18 is between 0 and 1. In rarer cases, however, may be larger than , in which case the argument to is negative and there is no solution to 5.18. If this happens, we can simply set r to its minimum allowable value (which we have assumed is 0).
One major limitation of policies as formulated above is that p is very hard to estimate. But there is a close relationship between p and the service level (see Section 4.3.4.2): As p increases, it's more costly to stock out, so the service level should increase. In practice, many firms would rather omit the stockout cost from the objective function and add a constraint requiring the service level to be at least a certain value.
First suppose that we wish to impose a type‐1 service level constraint. That is, we want to require the probability that no stockouts occur in a given cycle to be at least . Since stockouts occur if and only if the lead‐time demand is greater than r, this probability is simply . The expected cost function we wish to minimize is identical to 5.16 except it no longer contains a term for the stockout cost. Therefore, we need to solve
At optimality, the constraint 5.20 will always hold as an equality. (Why?) Therefore, the optimal reorder point is given by . If the lead‐time demand is normally distributed , then the optimal reorder point is
As we know from Section 4.3.2, this is exactly the form of the optimal solution to the newsvendor problem. As in the newsvendor problem, the first term of 5.21 represents the cycle stock (to meet the expected demand during the lead time), while the second term represents the safety stock (to meet excess demand during the lead time), since the safety stock is given by .
What about Q? Well, once r is fixed, we can ignore the constraint, and the term in the objective function 5.19 is a constant. What's left in 5.19 is exactly equal to the EOQ cost function (3.3). Therefore, we set Q to the EOQ value.
The expected cost of this solution is given by
(The first equality follows from the fact that , the mean lead‐time demand, equals . The second equality follows from (3.5).) This is an exact solution to the approximate model with a type‐1 service level constraint. This approach is often used as an approximation even when p is known; see Section 5.3.3. It is important in other ways, as well; for example, we will make use of it when we discuss the location model with risk pooling (LMRP) in Section 12.2.
Now consider a type‐2 service level constraint; we want to require the fill rate to be at least . We know that the average proportion of demands that stock out in each cycle is , so we need to replace 5.20 with
The resulting problem is significantly harder to solve: Since 5.23 contains both Q and r, we can no longer solve first for r and then solve independently for Q. Nevertheless, a reasonable approximation is simply to set (as in the case of type‐1) and compute r using . There is a more accurate method that involves a more complex formula for Q that is solved simultaneously with 5.18; see Nahmias (2005) for details.
There are important connections between the EOQ problem with planned backorders (EOQB; Section 3.5) and policies with continuous demand distributions. We explore these connections further in Section 5.4. The EOQB approximation for finding near‐optimal r and Q makes use of the EOQB, setting Q using (3.27) and r using Lemma 5.2. This approach has a fixed worst‐case error bound of that we will prove in Section 5.4, and an even tighter bound of 11.8% (which we will not prove).
Another common approximation for r and Q is to convert the inventory‐cost parameters into a service level and then to use the approach described in Section 5.3.1.3 for type‐1 service level constraints. In particular,
where . The safety stock is given by . The expected inventory process can be thought of as being decomposed into two parts, a “top” part that looks like an EOQ curve and a “bottom” part that is flat, with a height of s, the safety stock. We therefore refer to this as the EOQ+SS approximation.
The EOQ+SS approximation should not be confused with the EOQB approximation discussed in Section 5.3.2. Although both approaches use the EOQ(B) model to approximate an policy, they do so in different ways. Importantly, the EOQ+SS approximation does not have a fixed worst‐case error bound (see Problem 5.18), although some authors mistakenly apply Zheng's (1992) worst‐case bound of to it. Nevertheless, it is a reasonable approximation that performs well if provides an acceptable service level.
A similar approach can be used when the lead time itself is stochastic. Suppose the lead time L has mean and standard deviation (in years). Then the lead‐time demand has mean and variance
where, as usual, and are the mean and variance of the demand per year. (See Problem 5.16.) Equations 5.21 and 5.22 still hold under these new definitions of and . This approach is used in Case Study 5.5.1.
From 5.8,
where
by (C.12). Let be the second‐order loss function for the lead‐time demand distribution (see Section C.3.1):
Then we can rewrite as
Therefore,
Let's consider the term. We typically set r so that stockouts are unlikely during the lead time, i.e., so that the lead‐time demand is unlikely to exceed r. It is therefore even less likely to exceed . Since equals the expected value of the square of the amount by which the lead‐time demand exceeds , it, too, is likely to be small. For example, using the parameters in Example 5.2 and from Example 5.1, is less than .
Therefore, Hadley and Whitin (1963) propose assuming and then approximating as
Taking partial derivatives, we get
and
using the fact that (see (C.20)). Equations 5.28 and 5.29 can be solved for r and Q using an iterative method similar to that for the EIL approximation in Algorithm 5.1.
In fact, a similar approach can be used directly on 5.27, iteratively solving two optimality equations analogous to 5.28 and 5.29. This approach provides an exact (not heuristic) solution to find the optimal parameters for an policy (Farvid and Rosling, 2014).
Figure 5.4(a) plots the relative error of each of the four approximations described above on 20 randomly generated instances. The relative error is calculated as , where is the solution returned by the approximation, is the optimal solution, and is the exact cost function, given by 5.7. The mean and maximum relative error are given in the first set of columns in Table 5.1. Despite the fact that they are perhaps the two most commonly taught and used approaches, the EIL and EOQ+SS approximations perform the worst, with mean relative errors of over 30% and 14%, respectively. The other two approximations perform much better, with mean errors below 2%. On the other hand, they are more difficult to implement, since they require solving 5.9 (in the EOQB approximation) or computing (in the loss‐function approximation).
In Theorem 5.5, we will show that the cost is relatively insensitive to errors in Q. This suggests that the poor performance of the EIL and EOQ+SS is largely driven by their poor choices of r, rather than of Q. Indeed, if we alter each of the approximations to discard r at the end and instead set , the performance is much better, with mean errors below 2% for all four approximations; see Figure 5.4(b) and the second set of columns in Table 5.1. (Note that the performance of the EOQB approximation is the same in both experiments, since that approximation already sets .)
Table 5.1 Mean and maximum error of approximations.
Original | With | |||
Approximation | Mean | Max | Mean | Max |
EIL | 0.320 | 0.662 | 0.003 | 0.013 |
EOQB | 0.017 | 0.044 | 0.017 | 0.044 |
EOQ+SS | 0.147 | 0.311 | 0.015 | 0.072 |
Loss‐function | 0.003 | 0.024 | 0.002 | 0.020 |
We now return to the exact model from Section 5.2. We have two main goals in this section. First, we will analyze the properties of optimal solutions (and their costs) for policies, by deriving optimality conditions for r and Q and then proving properties of the resulting optimal solutions. Second, we will compare policies to the EOQB model and prove that, if the EOQB model is used as a heuristic for optimizing r and Q, as discussed in Section 5.3.2, the resulting error has a fixed bound. We do this by treating the EOQB as a deterministic policy, a reasonable interpretation since the two models include the same costs and both allow backorders. Our analysis in this section is based primarily on the work of Zheng (1992).
Let equal the expected cost per year as a function of Q, assuming r is set optimally for that Q—that is,
Let be the value of at or, equivalently, at :
One can show (see Problem 5.8) that
Therefore, from 5.7, we can write
which expresses the expected total cost as a function of Q only, not r. One can show that is convex. Finally, let
be the area between and the line at height ; see Figure 5.5.
The following theorem provides a surprisingly simple condition under which Q minimizes (and therefore minimizes ). We'll use to denote the minimizer of .
Therefore, the optimal length of the bar to drop into the “bowl” is the Q such that the area between the bar and the bowl equals . Unfortunately, we can't generally determine in closed form, since depends on , which in turn depends on , which also cannot be found in closed form. However, can be found through a straightforward search; see Section 5.4.1.
Algorithm 5.2 uses Theorem 5.2 to find the exact optimal values of r and Q for a continuous‐review policy with continuously distributed demand. The algorithm is basically a bisection search over Q, with an inner step that finds for each candidate value of Q. The bounds in the initialization step come from Theorem 5.3, below. In the termination criterion, is the desired tolerance.
Recall that is the minimizer of . Let
Then we can rewrite the cost function as
where
The first term in 5.37, , represents the noncontrollable cost in the policy. Even if we could keep the inventory position at at all times, by constantly placing orders, we could not avoid the cost —it is a consequence of the randomness in the demand. Of course, we cannot constantly place orders (since there is a fixed cost for each order), so the inventory position will deviate from the ideal level , and the inventory costs will increase from . By varying the order quantity Q, we adjust the trade‐off between fixed and inventory costs. The increase in cost over and above is the controllable cost, and this is captured by , the second term of 5.37.
As we know from Section 5.3.2, the EOQB (Section 3.5) provides an approximation of an policy. In fact, we can view the EOQB as a special case of an policy obtained by assuming the lead‐time demand is deterministic, i.e., that . In this section, we'll use this relationship to compare the optimal parameters and their resulting expected cost to those of the EOQB model, and then to prove a bound on the worst‐case error that can result from the EOQB approximation. Throughout this section, a subscript d denotes the deterministic model, i.e., the EOQB.
Since , the inventory cost rate 5.5 simplifies to
is minimized by and . This is not surprising: If the demand is deterministic, the inventory cost (i.e., the noncontrollable cost ) equals 0 if the inventory position is kept equal to the lead‐time demand. The functions and , and their minimizers, are plotted in Figure 5.6.
Note that
for all (Problem 5.9). Moreover, approaches asymptotically as : As , each additional unit of inventory position (y) will almost certainly not be demanded and will therefore result in an additional unit of on‐hand inventory, at a cost of h. Similarly, as , each reduction of one unit in y will almost certainly lead to one additional stockout, at a cost of p.
Let , , , and be the deterministic‐model versions of , , , and , respectively; that is, they are defined by 5.7, 5.9, 5.30, and 5.31 but with substituted for . (See Figure 5.7.) We have
Let minimize ; from Theorem 3.5, we know that
In fact, one can derive 5.43 and the other two equations in Theorem 3.5 using the analysis given so far in this section, treating the EOQB explicitly as a special case of an policy. (See Problem 5.14.)
The fact that is also evident from Figure 5.7. The upper bound of does not provide much intuition but does provide a useful upper bound for an iterative search for , as in Algorithm 5.2.
Let be the optimal cost in the stochastic model, be the optimal controllable cost in the stochastic model, and be the optimal cost in the deterministic model. The following theorem sheds light on the relationships among these costs. The last inequality of the theorem is especially impressive, since it succinctly relates the optimal costs and solutions of the three most fundamental inventory models: the EOQ(B), the newsvendor problem, and an policy!
The sensitivity analysis result for the EOQ model (Theorem 3.2) also applies to the EOQB (see Problem 3.14); converted to the notation in this ssection, we get
The cost function turns out to be even flatter (with respect to Q) for policies:
The question now is, how accurate is the EOQB approximation? Zheng (1992) proves a fixed worst‐case bound of on the error that results from using the EOQB solution:
Like many worst‐case error bounds, the bound in Theorem 5.6 overestimates the actual error bound obtained in practice. Zheng (1992) reports that, in computational results, the actual gap was less than 1% for 80.0% of the instances tested and less than 2% for 96.3%, with a maximum gap of only 2.9%. Table 5.1 reports similar results.
This raises the question of whether is the best possible bound. The answer is no: Axsäter (1996) proves that the error is no more than , or 11.8%. This bound is tight, in the sense that there are instances whose error comes arbitrarily close to , but these instances use pathological demand distributions that do not resemble real inventory systems.
Suppose now that the demand is discrete: Individual customers arrive randomly, each demanding one unit of the product. The number of demands in 1 year has a Poisson distribution with rate . Consequently, the lead‐time demand D has a Poisson distribution with rate ; the random variable D has pmf f and cdf F.
Since an order is placed immediately when reaches r, at any time. As in the model with continuous demands in Section 5.2, the inventory position spends equal time in each of these states: has a discrete uniform distribution on the integers , so for all . (See, e.g., Zipkin (2000) for a proof.) A discrete version of the conservation‐of‐flow equations (4.41) and (4.43) hold, so when , inventory (holding and stockout) costs accumulate at a rate of , given by 5.5 using the discrete distribution for D. Therefore, the expected total cost per year is given by
which is the discrete analogue of 5.7. As before, the function is jointly convex in Q and r.
Suppose we fix Q and we want to find , the best r for that Q. To do this, we need to choose r so that are as small as possible. In other words, we want to find the Q best inventory positions to minimize the sum in 5.48. Since is convex, these Q best inventory positions are nested, in the sense that, if is optimal for Q, then either or is optimal for .
Figure 5.8 depicts these nested inventory positions. The solid vertical lines represent the inventory positions that are optimal for Q, while the dashed lines represent possible inventory positions to add for . The question is, which is the better inventory position to add, (as in Figure 5.8(a)) or (Figure 5.8(b))? If , then we set ; otherwise, .
Note that if , then 5.48 simplifies to
The first term is a constant, so is optimized by optimizing . From Theorem 4.3, , the minimizer of , is the smallest S such that
and the optimal r is given by
In other words, whenever the inventory position falls to or smaller, we order up to . This is exactly a base‐stock policy under discrete demand. Thus, under discrete demand and continuous review, a base‐stock policy is a special case of an policy.
We can find the optimal Q and r recursively, as follows. We start with and set , where optimizes from 5.49, i.e., where is the smallest S satisfying 5.50. We then iterate through consecutive integer values of Q, determining using as described above. Since is convex in Q, we can stop as soon as we find that . This algorithm was introduced by Federgruen and Zheng (1992). Pseudocode is given in Algorithm 5.3.
For each method, report the values of r and Q you found, as well as the corresponding expected annual cost from 5.7.
For each method, report the values of r and Q you found, as well as the corresponding expected cost per week from 5.48.
Each copy purchased by the store costs c. Demands are backordered, in the sense that a customer wanting to rent the movie but finding that it is out of stock will return on another day to try again. Since this movie has been designated as a “guaranteed in stock” title, each backordered demand incurs a stockout cost of g, the cost of providing a free rental to the customer.
Assuming that backordered customers check back frequently to see whether the movie is in stock and rent it quickly when it is available, this system can be modeled as an queue, where S is the number of copies of the DVD owned by the store. It can be shown that the probability of a stockout in an queue is approximately
where is the standard normal cdf and (in queuing terminology, the “offered load”).
Hint: Argue that it is sufficient to prove the result with respect to increases in rather than K.
You may use the properties in Problem 5.7 without proof.
Assume that for some constant but that can vary independently of and .
Let be the expected cost function of the exact model under lead‐time demand. Let be the optimal parameters for this system and be the optimal cost; that is,
Similarly, let be the optimal parameters for the system with lead‐time demand, and let .
Prove that
( does not have a precise interpretation. But it is, in a sense, a quantity for the newsvendor model that is analogous to for the EOQB, since in the EOQB, the optimal order quantity equals the optimal cost times .)
Prove that
Hint: First prove that
for all . (You may use the result of Problem 5.15 without proof.) Then use this to prove the result.